A) \[50\,\Omega \]
B) \[100\,\Omega \]
C) \[200\,\Omega \]
D) \[400\,\Omega \]
Correct Answer: B
Solution :
When \[C\] is removed circuit becomes\[R-L\] circuit hence \[\tan \frac{\pi }{3}=\frac{{{X}_{L}}}{R}\] ? (i) When \[L\] \[\text{is}\] removed circuit is becomes \[R-C\] circuit hence, \[\tan \frac{\pi }{3}=\frac{{{X}_{C}}}{R}\] ? (ii) From Eqs. (i) and (ii), we obtain\[{{X}_{L}}={{X}_{C}}\] This is the condition of resonance and in resonance\[Z=R=100\Omega \]
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