A) \[75{}^\circ C\]
B) \[67{}^\circ C\]
C) \[33{}^\circ C\]
D) \[25{}^\circ C\]
Correct Answer: A
Solution :
Temperature of interface \[\theta =\frac{{{K}_{1}}{{\theta }_{1}}{{l}_{2}}+{{K}_{2}}{{\theta }_{2}}{{l}_{2}}}{{{K}_{2}}{{l}_{1}}+{{K}_{1}}{{l}_{2}}}\] According to \[{{K}_{cu}}=9\,\,{{K}_{s}}\] Let \[{{K}_{s}}={{K}_{2}}=K\] \[\therefore \] \[{{K}_{cu}}=9K\] \[\theta =\frac{9K\times 100\times 6+K\times 0\times 18}{9K\times 6+K\times 18}\] \[\theta =\frac{5400K}{72K}={{75}^{o}}C\]
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