2. Solved Papers
  3. RAJASTHAN PMT

RAJASTHAN PMT Rajasthan - PMT Solved Paper-2010

  • question_answer
    In the adjoining figure, four capacitors are shown with their respective capacities and the PD applied. The charge and the PD across the \[4\mu F\] capacitor will be

    A)  \[600\,\mu C;\,150\,V\]              

    B)  \[300\,\mu C;\,75\,V\]

    C)  \[800\,\mu C;\,200V\]   

    D)         \[580\,\mu C;\,145V\]

    Correct Answer: D

    Solution :

    Total capacitance\[\frac{1}{C}=\frac{1}{20}+\frac{1}{8}+\frac{1}{12}\] \[\Rightarrow \]                                 \[C=\frac{120}{31}\mu F\] Total charge                 \[Q=CV=\frac{120}{31}\times 300=1161\mu C\] Charge through \[4\mu F\] condenser                     \[=\frac{1161}{2}=500\mu C\] and potential difference across it                     \[=\frac{580}{4}=145\,\,V\]


You need to login to perform this action.
You will be redirected in 3 sec spinner