A) \[\frac{{{d}^{2}}x}{d{{t}^{2}}}-{{A}^{2}}x=0\]
B) \[\frac{dx}{dt}+{{A}^{2}}x=0\]
C) \[\frac{{{d}^{2}}x}{dt}+{{A}^{2}}{{x}^{2}}=0\]
D) \[\frac{{{d}^{2}}x}{d{{t}^{2}}}+{{A}^{2}}x=0\]
Correct Answer: D
Solution :
The displacement \[x\] as a function of time \[t\] of a simple harmonic motion is represented by\[\frac{{{d}^{2}}x}{d{{t}^{2}}}+{{A}^{2}}x=0\], where \[A\] is a positive constant. where A is a positive constant
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