A) \[3.3\times {{10}^{13}}\,Hz\]
B) \[8.0\times {{10}^{14}}\,Hz\]
C) \[1.65\times {{10}^{15}}\,Hz\]
D) \[9.9\times {{10}^{15}}\,Hz\]
Correct Answer: B
Solution :
Given,\[f=3.3eV=3.3\times 1.6\times {{10}^{-19}}V\] We know that \[f=hv\] \[v=\frac{f}{h}\] \[v=\frac{3.3\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}=0.8\times {{10}^{15}}Hz\] \[v=8.0\times {{10}^{14}}Hz\]
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