A) \[8,\,\,6\]
B) \[4,\,\,6\]
C) \[8,\,\,8\]
D) \[6,\,\,6\]
Correct Answer: D
Solution :
(i) The structure of \[{{H}_{2}}S{{O}_{5}}\] is \[H-O-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{S}}}\,-O-O-H\] As it is clear by the structure that two oxygen atom has peroxide linkage and their oxidation state is -1. Thus, we can calculate oxidation number (state) of sulphur in \[{{H}_{2}}S{{O}_{5}}\] as \[\underset{(for\,\,H)}{\mathop{2\times (+1)}}\,+\underset{(for\,\,S)}{\mathop{x}}\,+\underset{(for\,\,O-O)}{\mathop{2\times (-1)}}\,\] \[\underset{\begin{smallmatrix} (for\,\,other \\ three\,\,O\,\,atoms) \end{smallmatrix}}{\mathop{+3\times (-2)=0}}\,\] or \[x=+6\] (ii) Oxidation state (number) of\[Cr\]in\[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] \[\underset{(for\,\,K)}{\mathop{2\times (+1)}}\,\underset{(for\,\,Cr)}{\mathop{+2\times x}}\,\underset{(for\,\,O\,\,atoms)}{\mathop{+7\times (-2)=0}}\,\] or \[x=+6\]
You need to login to perform this action.
You will be redirected in
3 sec
