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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2011

  • question_answer
    300 cal of heat is supplied to raise the temperature of 50 g of air from \[20{}^\circ C\] to \[30{}^\circ C\] without any change in its volume. Change in internal energy per gram of air is

    A)  zero                                     

    B)  0.6 cal

    C)  1.2 cal                  

    D)         6.0 cal

    Correct Answer: D

    Solution :

    Given,   \[\Delta Q=300\,\,cal\] and        \[m=50\,\,g\] We know that                 \[\Delta U=\Delta Q\]                 \[\Delta U=300\,\,cal\] Change internal energy per gram                 \[\Delta U=\frac{300}{50}=6\,\,cal\]


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