RAJASTHAN PMT Rajasthan - PMT Solved Paper-2011

  • question_answer
    If the de-Broglie wavelength of the fourth Bohr orbit of hydrogen atom is\[4\overset{\text{o}}{\mathop{\text{A}}}\,\], the circumference of the orbit will be

    A) \[4\overset{\text{o}}{\mathop{\text{A}}}\,\]                                   

    B) \[4\,\,nm\]

    C) \[16\,\,\overset{\text{o}}{\mathop{\text{A}}}\,\]          

    D)        \[16\,\,nm\]

    Correct Answer: C

    Solution :

    According to Bohrs postulate and de-Broglie equation                 \[2\pi r=n\lambda \] Here, \[2\pi r=\]circumference of the orbit                      \[n=4\]                     \[\lambda =4\overset{\text{o}}{\mathop{\text{A}}}\,\] \[\therefore \]  \[2\pi r=4\times 4\]                        \[=16\overset{\text{o}}{\mathop{\text{A}}}\,\]


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