Railways RRB (Assistant Loco Pilot & Technician) Solved Paper-2 (2013)

  • question_answer
    \[_{a}{{\mu }_{g}}=\frac{3}{2}\] and \[_{a}{{\mu }_{w}}=\frac{4}{3}\]. If the speed of light in glass is \[2.00\times {{10}^{8}}\text{ }m/s,\] the speed in water will be

    A) \[2.67\times {{10}^{8}}m/s\]         

    B) \[~2.25\times {{10}^{8}}\text{ }m/s\]

    C) \[1.78\times {{10}^{8}}\text{ }m/s\]         

    D)  \[1.50\times {{10}^{8}}\text{ }m/s\]

    Correct Answer: B

    Solution :

    \[_{a}{{\mu }_{g}}=\frac{{{V}_{a}}}{{{V}_{g}}}\] \[\Rightarrow \] \[\frac{3}{2}=\frac{{{V}_{a}}}{2\times {{10}^{8}}}\Rightarrow {{V}_{a}}=3\times {{10}^{8}}m/s\] \[\Rightarrow \] \[\frac{4}{3}=\frac{3\times {{10}^{8}}}{{{V}_{w}}}\] \[\Rightarrow \] \[{{V}_{w}}=\frac{9}{4}\times {{10}^{8}}=2.25\times {{10}^{8}}\] \[_{a}{{\mu }_{g}}=\frac{{{V}_{a}}}{{{V}_{g}}}\] \[\Rightarrow \] \[\frac{3}{2}=\frac{{{V}_{a}}}{2\times {{10}^{8}}}\Rightarrow {{V}_{a}}=3\times {{10}^{8}}m/s\] \[\Rightarrow \] \[\frac{4}{3}=\frac{3\times {{10}^{8}}}{{{V}_{w}}}\] \[\Rightarrow \] \[{{V}_{w}}=\frac{9}{4}\times {{10}^{8}}=2.25\times {{10}^{8}}\]


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