A) \[1:2\]
B) \[1:3\]
C) \[2:1\]
D) None of these
Correct Answer: A
Solution :
Radius of circumcircle \[=\frac{1}{2}\] Diagonal of square \[=\frac{1}{2}\sqrt{2}a=\frac{a}{\sqrt{2}}\] \[\therefore \] Area of circumcircle \[=\frac{\pi {{a}^{2}}}{2}\] Radius of in circle \[=\frac{1}{2}\] of side of square \[=\frac{1}{2}a\] \[\therefore \] Area of in circle \[=\frac{\pi {{a}^{2}}}{4}\] Required ratio \[=\frac{\frac{\pi {{a}^{2}}}{4}}{\frac{\pi {{a}^{2}}}{2}}=\frac{1}{2}=1:2\]
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