A) 400
B) 465
C) 490
D) 520
Correct Answer: A
Solution :
Volume of silver coins \[=\pi \times {{\left( \frac{1.75}{2} \right)}^{2}}\times \frac{2}{10}\] \[=0.48125\,\,c{{m}^{3}}\] \[=5.5\times 10\times 3.5\] \[=192.5\,\,c{{m}^{3}}\] \[\therefore \] Number of silver coins \[=\frac{192.5}{0.48125}\] \[=400\]
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