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Railways R.R.C. (Delhi) Solved Paper Held on 1st Shift 23-11-2014

  • question_answer
    If\[{{(x+y-2)}^{2}}+{{(3x-2y-1)}^{2}}=0\] then the values of x and y are respectively?

    A) 1, 1      

    B) \[1,\,\,-1\]

    C) \[-1,\,1\]                        

    D) \[-1,\,\,-1\]

    Correct Answer: A

    Solution :

    If \[{{(x+y-2)}^{2}}+{{(3x-2y-1)}^{2}}=0\] Then,\[x+y-2=0\]           ...(1) \[3x-2y-1=0\]                 ...(2) On solving eqn. (1) and (2) \[x=+1,\,\,y=+1\]


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