A) 3A
B) 9A
C) 81A
D) \[9\times {{[p\,\,/\,\,(2\pi )]}^{2}}\times A\]
Correct Answer: C
Solution :
Suppose radius of circle = r Then, Perimeter, P=\[2\pi r\] and Area, A\[=\pi {{r}^{2}}\] So, A \[=\frac{{{p}^{2}}}{4\pi }\] ... (1) Now, \[9p=2\pi r\] \[=\frac{9p}{2\pi }\] Area of circle \[=\]\[\pi {{r}^{2}}\] \[=\pi {{\left( \frac{9p}{2\pi } \right)}^{2}}\] \[=\frac{81\,\,{{p}^{2}}}{4\pi }\] = 81 A [From eqn., ...(1)
You need to login to perform this action.
You will be redirected in
3 sec
