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Railways R.R.C. (Hajipur) Solved Paper Held on 1st Shift 30-11-2014

  • question_answer
    \[(2{{\sin }^{2}}30{}^\circ -3co{{s}^{2}}45{}^\circ +{{\tan }^{2}}60{}^\circ )\]= ?

    A) 1                                 

    B) 2

    C) 4                                 

    D) 5

    Correct Answer: B

    Solution :

    \[?=2\,\,{{\sin }^{2}}\,\,30{}^\circ -3\,\,{{\cos }^{2}}\,\,45{}^\circ +{{\tan }^{2}}\,\,60{}^\circ \] \[=2\times \frac{1}{4}-3\times \frac{1}{2}+3\] \[=\frac{1}{2}-\frac{3}{2}+3=2\]


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