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Railways R.R.C. (Hazipur) Solved Paper Held on 1-12-2013

  • question_answer
    If \[\frac{1}{1+\frac{1}{1+\frac{1}{x}}}=2,\]then \[x=?\]

    A) \[-\frac{1}{3}\]                         

    B) \[-1\]

    C) \[\frac{1}{3}\]                          

    D) 1

    Correct Answer: A

    Solution :

         \[\frac{1}{1+\frac{1}{1+\frac{1}{x}}}=2\] \[\Rightarrow \]   \[\frac{1}{1+\frac{1}{x+1}}=2\] \[\Rightarrow \]   \[\frac{x+1}{2x+1}=2\] \[\Rightarrow \]   \[x+1=4x+2\] \[\Rightarrow \]   \[3x=-1\] \[\Rightarrow \]   \[x=-\frac{1}{3}\]


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