A) 2
B) \[2\sqrt{4}\]
C) \[6\sqrt{2}\]
D) \[\sqrt{6}\]
Correct Answer: A
Solution :
\[\frac{\sqrt{24}+\sqrt{216}}{\sqrt{96}}=\frac{\sqrt{4\times 6}+\sqrt{6\times 6\times 6}}{\sqrt{16\times 6}}\] \[=\frac{2\sqrt{6}+6\sqrt{6}}{4\sqrt{6}}\] \[=\frac{8\sqrt{6}}{4\sqrt{6}}\] \[\frac{=4\times 2\sqrt{6}}{4\sqrt{6}}=2\]
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