A) \[\frac{2}{3}\]
B) \[1\,\,\frac{1}{4}\]
C) \[1\,\,\frac{2}{3}\]
D) \[1\,\,\frac{1}{2}\]
Correct Answer: D
Solution :
\[?=\frac{4\frac{2}{21}-2\frac{13}{14}+1\frac{5}{7}\div 5\frac{1}{7}}{1\frac{7}{9}\times 2\frac{1}{48}\div 3\frac{16}{27}}\] \[=\frac{\frac{86}{21}-\frac{41}{14}+\frac{12}{7}\times \frac{7}{36}}{\frac{16}{9}\times \frac{97}{48}\times \frac{27}{97}}\] \[=\frac{86}{21}-\frac{41}{14}+\frac{1}{3}\] \[=\frac{172-123+14}{42}\] \[=\frac{63}{42}=\frac{3}{2}\] \[?=1\frac{1}{2}\]
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