Railways R.R.C. (Patna) Solved Paper Held on 1st_Shift 23-11-2014

  • question_answer
    \[\frac{\sin 30{}^\circ \cos 45{}^\circ }{\tan 60{}^\circ }=?\]

    A) \[\frac{2}{\sqrt{3}}\]                             

    B) \[\frac{\sqrt{6}}{12}\]

    C) \[\sqrt{\frac{2}{3}}\]                             

    D) \[2\sqrt{3}\]

    Correct Answer: D

    Solution :

    \[?=\frac{\sin 30{}^\circ \cos 45{}^\circ }{\tan 60{}^\circ }\] \[=\frac{\frac{1}{2}\times \frac{1}{\sqrt{2}}}{\sqrt{3}}=\frac{1}{2\sqrt{6}}\times \frac{\sqrt{6}}{\sqrt{6}}\]  \[=\frac{\sqrt{6}}{12}\]


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