A) 1
B) \[\sqrt{2}\]
C) 2
D) \[2\sqrt{2}\]
Correct Answer: B
Solution :
The maximum value of (\[\sin \theta +\cos \theta \]) \[=\sqrt{{{(1)}^{2}}+{{(1)}^{2}}}\] \[=\sqrt{1+1}=\sqrt{2}\]
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