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Railways R.R.C. (Patna) Solved Paper Held on 1st_Shift 23-11-2014

  • question_answer
    A cistern has two pipes. One can fill it with water in 8 hours and other can empty it in 5 hours. In how many hours will the cistern be emptied if both pipes are opened together when\[\frac{3}{4}\] of the cistern is already full of water?

    A) \[3\,\,\frac{1}{3}\] hours            

    B) 6 hours

    C) 10 hours                       

    D) \[13\frac{1}{3}\] hours

    Correct Answer: A

    Solution :

    Remaining tank \[=1-\frac{3}{4}=\frac{1}{4}\] Then, required time\[=\frac{1}{4}\,\,\left[ \frac{8\times 5}{8-5} \right]\] \[=\frac{10}{3}=3\,\,\frac{1}{3}\]hours


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