question_answer

A man earns Rs. 600 per month more than his wife, One-tenth of the man?s salary and one-sixth of the wife?s salary amount to Rs. 1,500, which is saved every month. Find their incomes.

Answer:

Let wife's monthly income \[=Rs.\text{ }x\]

Then man's monthly income \[=Rs.\text{ (}x+600)\]

According to the question,

\[\frac{1}{10}(x+600)+\frac{1}{6}(x)=1,500\]

\[\frac{3(x+600)+5x}{30}=1,500\]

\[3x+1,800+5x=45,000\]

\[8x=45,000-1,800\]

\[x=\frac{43,200}{8}=5,400\]

Wife?s income \[=Rs.\,\,x=Rs.\,\,5,400\]

Man?s income = \[=Rs.\,(\,x+600)=Rs.\,\,6,000\]