question_answer

Evaluate: \[10.\frac{1-{{\cot }^{2}}45{}^\circ }{1+{{\sin }^{2}}90{}^\circ }\]

Answer:

\[10.\frac{1-{{\cot }^{2}}45{}^\circ }{1+{{\sin }^{2}}90{}^\circ }=10.\frac{1-{{(1)}^{2}}}{1+{{(1)}^{2}}}\]

\[=10.\left( \frac{0}{2} \right)=0\]