Answer:
Given, sum of zeroes, \[(S)=\sqrt{3}\] Product of zeroes, \[(P)=\frac{1}{\sqrt{3}}\] Quadratic polynomial is given as, \[{{x}^{2}}-Sx+P\] \[={{x}^{2}}-\sqrt{3}x+\frac{1}{\sqrt{3}}\] \[=\frac{\sqrt{3}{{x}^{2}}-3x+1}{\sqrt{3}}\] \[=\frac{1}{\sqrt{3}}(\sqrt{3}{{x}^{2}}-3x+1)\]
You need to login to perform this action.
You will be redirected in
3 sec