Answer:
Diameter of the tent \[(d)=4.2\text{ }m\] \[\therefore \] Radius of the tent \[(r)=2.1\text{ }m\] \[[\because \,\,r=\frac{d}{2}]\] Height of the cylindrical part of tent \[(h)=4\text{ }m\] Height of conical part \[(H)=2.8\text{ }m\] Slant height of conical part \[(l)=\sqrt{{{H}^{2}}+{{r}^{2}}}\] \[l=\sqrt{{{(2.8)}^{2}}+{{(2.1)}^{2}}}\] \[l=\sqrt{7.84+4.41}\] \[l=\sqrt{12.25}\] \[l=3.5\,cm\] Curved surface area of the cylinder \[=2\pi rh\] \[=2\times \frac{22}{7}\times 2.1\times 4\left[ \because \,\pi =\frac{22}{7} \right]\] \[=2\times 22\times 0.3\times 4\] \[=52.8{{m}^{2}}\] Curved surface area of conical tent \[=\pi rl\] \[=\frac{22}{7}\times 2.1\times 3.5\] \[=22\times 0.3\times 3.5\] \[=23.1\,{{m}^{2}}\] Total area of cloth required for building one tent = C.S.A. of cylinder + C.S.A. of conical tent \[=(52.8+23.1)\,{{m}^{2}}\] \[=75.9\text{ }{{m}^{2}}\] Cost of building one tent \[=75.9\times 100\] \[=Rs.\text{ }7590\] Total cost of 100 tents \[=Rs.\text{ (}7590\times 100)\] \[=Rs.\text{ 7,59,000}\] Cost to be borne by the associations (50% of the cost) \[=\frac{759000\times 50}{100}\] \[=Rs.\,379500\] Hence, the association will have to pay \[Rs.\text{ }379500\]. Values shown by associations are helping the flood victims and showing concern for humanity.
You need to login to perform this action.
You will be redirected in
3 sec
