Answer:
When two dice are thrown simultaneously, all possible outcomes are: Total number of all outcomes \[=6\times 6=36\] Favourable outcomes of getting the product as 6 are: (2, 3), (3, 2), (1, 6), (6, 1) Hence, number of favourable outcomes getting product as 6 is 4. Probability that the product of the two numbers on the top of the die is 6 \[=\frac{4}{36}\] \[=\frac{1}{9}\]
You need to login to perform this action.
You will be redirected in
3 sec