Answer:
Height of the cylinder \[h=10\text{ }cm\] Radius of base of cylinder \[(r)=4.2\text{ }cm\] Now, Volume of cylinder \[=\pi {{r}^{2}}h\] \[=\frac{22}{7}\times 4.2\times 4.2\times 10\] \[=554.4\,\,c{{m}^{3}}\] Volume of hemisphere \[=\frac{2}{3}\pi {{r}^{3}}\] \[=\frac{2}{3}\times \frac{22}{7}\times 4.2\times 4.2\times 4.2\] \[=155.232\,\,c{{m}^{3}}\] Volume of the rest of the cylinder after scooping out the hemisphere from each end = Volume of cylinder\[-2\times \]Volume of hemisphere \[=554.4-2\times 155.232\] \[=554.4-310.464\]. \[=243.936\text{ }c{{m}^{3}}\]. The remaining cylinder is melted and converted into a new cylindrical wire of 1.4 cm thickness. So, radius of cylindrical wire \[=0.7\text{ }cm\] Volume of remaining cylinder = Volume of new cylindrical wire \[243.936=\pi {{R}^{2}}H\] \[243.936=\frac{22}{7}\times 0.7\times 0.7\times H\] \[\Rightarrow H=158.4\,\,cm\]
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