In Fig. 4, ABCD is a square of side 14 cm. Semi-circles are drawn with each side of square as diameter. Find the area of the shaded region, \[\left( use\,\pi =\frac{22}{7} \right)\] |
Answer:
Given, a square ABCD of side 14 cm Then, Area of square \[=\text{ (}side{{)}^{2}}\] \[={{(14)}^{2}}=196\text{ }c{{m}^{2}}\] 2 [Area of semicircle] \[=\pi \text{ }{{r}^{2}}\] \[=\frac{22}{7}\times \frac{14}{2}\times \frac{14}{2}=154\,c{{m}^{2}}\] Now, Area of shaded region = 2[Area of square\[\]2 (Area of semicircle)] \[=2\,[196-154]=2\times 42=84\text{ }c{{m}^{2}}\]
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