Answer:
Let length of tower is h In \[\Delta \,ABD\] \[\tan \,60{}^\circ =\frac{h}{4}\] ?(i) In \[\Delta \,ABC\] \[\tan \,30{}^\circ =\frac{h}{9}\] \[\cot (90{}^\circ -30{}^\circ )=\frac{h}{9}\] \[\cot \,60{}^\circ =\frac{h}{9}\] ?(ii) Multiplying eq. (i) and (ii), we get \[\tan \,60{}^\circ .\cot \,60{}^\circ =\frac{h}{4}\times \frac{h}{9}\] \[1=\frac{{{h}^{2}}}{36}\] \[h=6\,m\] Note: In this question, it has not been specified whether two points from tower are taken in same or opposite side we have taken these points on the same side of tower.
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