Answer:
Given, the base radius of cone, \[r=3.5\,cm\] Total height of cone, \[(h+r)=15.5\text{ }cm\] and base diameter of hemisphere \[=7\text{ }cm\] Now, \[h=(15.5-3.5)\text{ }cm=12\text{ }cm\] So, slant height, \[l=\sqrt{{{h}^{2}}+{{r}^{2}}}=\sqrt{{{(12)}^{2}}+{{(3.5)}^{2}}}\] \[=\sqrt{144+12.25}\] \[=12.5\,cm\] \[\therefore \] Total Surface Area \[=\pi rl+2\pi {{r}^{2}}\] \[=\frac{22}{7}\times 3.5\times 12.5+2\times \frac{22}{7}\times 3.5\times 3.5\] \[=\frac{22}{7}\times 3.5(12.5+2\times 3.5)\] \[=11(19.5)\] \[=214.5\,c{{m}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec