10th Class Mathematics Solved Paper - Mathematics-2016 Delhi Term-II Set-III

  • question_answer
    A toy is in the form of a cone of base radius 3.5 cm mounted on a hemisphere of base diameter 7 cm. If the total height of the toy is 15.5 cm, find the total surface area of the toy. \[\left( use\,\pi =\frac{22}{7} \right)\]

    Answer:

    Given, the base radius of cone, \[r=3.5\,cm\]
    Total height of cone, \[(h+r)=15.5\text{ }cm\]
    and base diameter of hemisphere \[=7\text{ }cm\]
    Now, \[h=(15.5-3.5)\text{ }cm=12\text{ }cm\]
    So, slant height,              \[l=\sqrt{{{h}^{2}}+{{r}^{2}}}=\sqrt{{{(12)}^{2}}+{{(3.5)}^{2}}}\]
                                        \[=\sqrt{144+12.25}\]
                                        \[=12.5\,cm\]
    \[\therefore \] Total Surface Area \[=\pi rl+2\pi {{r}^{2}}\]
                                        \[=\frac{22}{7}\times 3.5\times 12.5+2\times \frac{22}{7}\times 3.5\times 3.5\]
                                        \[=\frac{22}{7}\times 3.5(12.5+2\times 3.5)\]
                                        \[=11(19.5)\]
                                        \[=214.5\,c{{m}^{2}}\]


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