Answer:
Radius of the base of cylinder \[(r)=2.8\,m\] |
Radius of the base of the cone \[(r)=2.8\,m\] |
Height of the cylinder \[(h)=3.5\,m\] |
Height of the cone \[(H)=2.1\,m\]. |
Slant height of conical part \[(l)=\sqrt{{{r}^{2}}+{{H}^{2}}}\] |
\[=\sqrt{{{(2.8)}^{2}}+{{(2.1)}^{2}}}\] |
\[=\sqrt{7.84+4.41}\] |
\[=\sqrt{12.25}\] |
\[=3.5\,m\] |
Area of canvas used to make tent |
= CSA of cylinder + CSA of cone |
\[=2\times \pi \times 2.8\times 3.5+\pi \times 2.8\times 3.5\] |
\[=61.6+30.8\] |
\[=92.4\text{ }{{m}^{2}}\] |
Cost of 1500 tents at Rs. 120 per sq. m |
\[=1500\times 120\times 92.4\] |
\[=Rs.\,\,16,632,000\] |
Share of each school to set up the tents |
\[=\frac{16632000}{50}\] |
\[=Rs.\,332,640\] |
Value ? Be kind and help others in need. |
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