Answer:
Total apples \[=900\] \[P(E)=0.18\] \[\frac{No.\,\,of\,\,rotten\,\,apples}{Total\,\,no.\,\,of\,\,apples}=0.18\] \[\frac{No.\,\,of\,\,rotten\,\,apples}{900}=0.18\] No. of rotten apples \[=900\times 0.18\] \[=162\]
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