• # question_answer Two different dice are tossed together. Find the probability: (i) of getting a doublet (ii) of getting a sum 10, of the numbers on the two dice.

 Total outcomes on tossing two different dice = 36 (i) A: getting a doublet $A=\{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)\}$ $\therefore$ Number of favourable outcomes of $A=6$ $\therefore$      $P(A)=\frac{Favourable\,\,outcomes}{Total\,\,outcomes}$ $=\frac{6}{36}=\frac{1}{6}$ (ii) B: getting a sum 10. $B=\{(4,6),(5,5),(6,4)\}$ $\therefore$ Number of favourable outcomes of B = 3 $\therefore$      $P(B)=\frac{Favourable\,\,outcomes}{Total\,\,outcomes}$ $\therefore$              $=\frac{3}{36}=\frac{1}{12}$