question_answer

Two different dice are tossed together. Find the probability:

(i) of getting a doublet

(ii) of getting a sum 10, of the numbers on the two dice.

Answer:

Total outcomes on tossing two different dice = 36

(i) A: getting a doublet

\[A=\{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)\}\]

\[\therefore \] Number of favourable outcomes of \[A=6\]

\[\therefore \]      \[P(A)=\frac{Favourable\,\,outcomes}{Total\,\,outcomes}\]

\[=\frac{6}{36}=\frac{1}{6}\]

(ii) B: getting a sum 10.

\[B=\{(4,6),(5,5),(6,4)\}\]

\[\therefore \] Number of favourable outcomes of B = 3

\[\therefore \]      \[P(B)=\frac{Favourable\,\,outcomes}{Total\,\,outcomes}\]

\[\therefore \]              \[=\frac{3}{36}=\frac{1}{12}\]