• # question_answer Find the area of the shaded region in Fig. 2, where arcs drawn with centres A, B, C and D intersect in pairs at mid-points P, Q, R and S of the sides AB, BC, CD and DA respectively of a square ABCD of side 12 cm, [Use $\pi =3.14$]

 Given, ABCD is a square of side 12 cm. P, Q, R and S are the mid points of sides AB, BC, CD and AD respectively. Area of shaded region = Area of square $-4\times$Area of quadrant $={{a}^{2}}-4\times \frac{1}{4}\pi {{r}^{2}}$ $={{(12)}^{2}}-3.14\times {{(6)}^{2}}$ $=144-3.14\times 36$ $=144-113.04$ $=30.96\,\,c{{m}^{2}}$