• # question_answer Given $\Delta \,ABC\sim \Delta \,PQR$, if $\frac{AB}{PQ}=\frac{1}{3}$, then find $\frac{ar\,\,\Delta \,ABC}{ar\,\,\Delta \,\,PQR}$.

 Given, $\Delta \text{ }ABC\tilde{\ }\Delta \text{ }PQR$ And                  $\frac{AB}{PQ}=\frac{1}{3}$ Now         $\frac{ar(\Delta \,ABC)}{ar(\Delta \,PQR)}=\frac{A{{B}^{2}}}{P{{Q}^{2}}}$ $={{\left( \frac{1}{3} \right)}^{2}}=\frac{1}{9}$

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