• # question_answer 8) In fig. 1, ABCD is a rectangle. Find the values of x and y.

 Given, ABCD is a rectangle. $\therefore$                  $AB=CD$ $\Rightarrow$               $30=x+y$ Or                     $x+y=30$ Similarly,           $AD=BC$                                                                    ?(i) $\Rightarrow$               $14=x-y$ Or                  $x-y=14$ On adding eq. (i) and (ii), we get                                                               ?(ii) $2x=44$ $\Rightarrow$               $x=22$ Putting the value of x in eq. (i), we get $22+y=30$ $\Rightarrow$               $y=30-22$ $\Rightarrow$                 $y=\text{ }8$ So,  $x=22,\text{ }y=8$.