(i) While studying the combination reaction on adding water to quick lime, name the product formed and write its colour. |
(ii) While studying the decompostion reaction by heating ferrous sulphate crystals in a test-tube, a product is formed in the test?tube. Name the product and write its colour. |
Answer:
(i) Quicklime (CaO) reacts vigorously with water to form slaked lime \[[Ca{{(OH)}_{2}}]\] which is white in colour. \[\underset{\begin{smallmatrix} \text{Calcium oxide} \\ \text{(Quick lime)} \end{smallmatrix}}{\mathop{CaO(s)}}\,\mathrm{ }+\mathrm{ }{{H}_{2}}O(l)\xrightarrow{\text{Combination}}\underset{\begin{smallmatrix} \text{Calcium hydroxide} \\ \text{(Slaked lime)(white)} \end{smallmatrix}}{\mathop{Ca{{(OH)}_{2}}(s)}}\,\] (ii) When ferrous sulphate is heated strongly, it decomposes to form brown coloured ferric oxide and sulphur dioxide gas and sulphur trioxide gas. \[\underset{\begin{smallmatrix} \text{Ferrous Sulphate} \\ \text{(green colour)} \end{smallmatrix}}{\mathop{2FeS{{O}_{4}}(s)}}\,\xrightarrow[\text{Decomposition}]{\Delta }\underset{\begin{smallmatrix} \text{Ferric oxide} \\ \text{(brown)} \end{smallmatrix}}{\mathop{F{{e}_{2}}{{O}_{3}}(s)}}\,+S{{O}_{2}}(g)+S{{O}_{3}}(g)\]
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