question_answer

An object is placed at a distance of 30 cm from a concave lens of focal length 15 cm. List four characteristics (nature, position, etc.) of the image formed by the lens.

Answer:

Given: \[u=-30\text{ }cm,f=-15\text{ }cm.\]

We know that,

\[\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\]

\[\frac{1}{v}-\frac{1}{(-30)}=\frac{1}{(-15)}\]

\[\frac{1}{v}=\frac{-1}{15}-\frac{1}{30}\]

\[\frac{1}{v}=\frac{-2-1}{30}=\frac{-3}{30}=\frac{-1}{10}\]

\[v=-10\,cm\]

Characteristics of image:

(i) The image is formed at a distance of 10 cm from the concave lens on the left side.

(ii) Image formed is virtual.

(iii) Image formed is erect.

(iv) The size of the image formed is diminished.