Answer:
The reaction of carboxylic acid with alcohol forms an ester. This process of formation of ester is called esterification.
\[C{{H}_{3}}COOH+C{{H}_{3}}C{{H}_{2}}OH\to C{{H}_{3}}COOC{{H}_{2}}C{{H}_{3}}+{{H}_{2}}O\]
Activity:
(i) Take 1 ml of ethanol and 1 ml of glacial acetic acid in a boiling tube and mix the contents well.
(ii) Add few drops of cone. \[{{H}_{2}}S{{O}_{4}}\] to it.
(iii) Warm the contents on a water bath for a few minutes.
(iv) Now pour the solution in a beaker containing 20-50 ml of water.
(v) A sweet fruity smell indicating formation of an ester is observed.
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