Uttarakhand PMT Uttarakhand PMT Solved Paper-2004

  • question_answer
    A force of 10 N acts on a body of mass 20 kg. for 10 seconds. The change in its momentum is :

    A)  50 kg-m/s

    B)  100 kg-m/s

    C)  300 kg-m/s

    D)  1000 kg-m/s

    Correct Answer: B

    Solution :

     Given: \[F=10\text{ }N,\text{ }m=20\text{ }kg,\] \[\Delta t=10\text{ }sec\] The change in momentum of the body is given by \[\Delta p=F\times \Delta t=10\times 10\] \[=100\text{ }kg-m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner