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Uttarakhand PMT Uttarakhand PMT Solved Paper-2004

  • question_answer
    The equivalent weight of a solid element is found to be 9. If the specific heat of this element is\[1.05\,Jg\,{{K}^{-1}},\]then its atomic weight is:

    A)  17          

    B)  21

    C)  25           

    D)  27

    Correct Answer: D

    Solution :

     By using: Valency of an element \[=\frac{Approximate\text{ }weight}{Equivalent\text{ }weight}\] \[=\frac{26.8/specific\text{ }heat}{Equivalent\text{ }weight}\] \[=\frac{26.8/1.05}{9}=2.835\cong 3\] Now, by using Atomic weight = Equivalent weight\[\times \]valency \[=9\times 3=27\]


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