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Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is \[45{}^\circ ,\]then its coefficient of friction will be:

    A)  1                  

    B)  2

    C) \[\sqrt{3}\]              

    D) \[\frac{\sqrt{3}}{2}\]

    Correct Answer: A

    Solution :

     The angle of inclination\[\theta =45{}^\circ \] The coefficient of static friction is given by \[\mu =\tan \theta =\tan 45{}^\circ =1\]


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