A) \[\frac{m\upsilon }{Be}\]
B) \[\frac{me}{B}\]
C) \[\frac{mE}{B}\]
D) \[\frac{Be}{m\upsilon }\]
Correct Answer: A
Solution :
The centripetal force on the electron due to circular path \[=\frac{m{{\upsilon }^{2}}}{r}\] ...(1) Force on the electron due to magnetic field is \[=Be\upsilon \] ...(2) Now equating the equation (1) and (2) We have \[\frac{m{{\upsilon }^{2}}}{r}=Be\upsilon \] (Where r is the radius of circular path) \[r=\frac{m\upsilon }{Be}\]
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