Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    The Bohrs orbit radius for the hydrogen atom \[(n=1)\]is approximately\[0.53\overset{o}{\mathop{\text{A}}}\,\]. The radius for the first excite state\[(n=2)\]orbit is:

    A)  \[0.27\overset{o}{\mathop{\text{A}}}\,\]           

    B)  \[1.27\overset{o}{\mathop{\text{A}}}\,\]

    C)  \[2.12\overset{o}{\mathop{\text{A}}}\,\]            

    D)  \[3.12\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: C

    Solution :

     The radius of\[{{n}^{th}}\]orbit of hydrogen atom \[{{r}_{n}}={{a}_{0}}\times {{n}^{2}}\] \[{{a}_{0}}=\] Bohrs radius \[=0.53\overset{o}{\mathop{\text{A}}}\,\] \[\therefore \] the radius for first excited state \[n=2,{{r}_{2}}={{a}_{0}}\times {{2}^{2}}\] \[{{r}_{2}}=0.53\times 4\] \[\overset{o}{\mathop{\text{A}}}\,=2.12\overset{o}{\mathop{\text{A}}}\,\]


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