A) 1L
B) 11.2 L
C) 22.4 L
D) 4 L
Correct Answer: A
Solution :
\[\because \] Vapour density of gas = 11.2 \[\therefore \]molecular mass \[=2\times V.D.\] \[=2\times 11.2=22.4\] \[\because \]22.4 g of gas occupy volume at NTP =22.4L \[\therefore \]1 g of gas occupies volume at NTP \[=\frac{22.4}{22.4}\times 1=1L\]
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