Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer A gas has a vapour density 11.2. The volume occupies by 1 g of the gas at NTP is:

    A)  1L    

    B)  11.2 L

    C)  22.4 L

    D)  4 L

    Correct Answer: A

    Solution :

     \[\because \] Vapour density of gas = 11.2 \[\therefore \]molecular mass \[=2\times V.D.\] \[=2\times 11.2=22.4\] \[\because \]22.4 g of gas occupy volume at NTP =22.4L \[\therefore \]1 g of gas occupies volume at NTP \[=\frac{22.4}{22.4}\times 1=1L\]


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