A) \[{{N}_{2}}O\]
B) \[NO\]
C) \[N{{O}_{2}}\]
D) \[{{N}_{2}}{{O}_{5}}\]
Correct Answer: C
Solution :
\[\underset{Lead\text{ }nitrate}{\mathop{2Pb(N{{O}_{2}})}}\,\xrightarrow[{}]{heat}2PnO+4N{{O}_{2}}+{{O}_{2}}\] Thus, on heating lead nitrate produce\[N{{O}_{2}}\].
You need to login to perform this action.
You will be redirected in
3 sec
