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Uttarakhand PMT Uttarakhand PMT Solved Paper-2006

  • question_answer
    Haemolytic jaundice is due to a dominant gene but only 10% of the people develops this disease. A heterozygous male marries a homozygous normal woman. What proportion of the children in population would be expected to have this disorder?

    A)  \[1/5\]            

    B)  \[1/10\]

    C)  \[1/20\]

    D)  \[1/2\]

    Correct Answer: C

    Solution :

    Aaxaa\[\to \]Aa,aai.e.,\[\frac{1}{2}\]aa and\[\frac{1}{2}\]Aaandinthe 10%  of population, its frequency will be\[\frac{1}{2}\times \frac{1}{10}=\frac{1}{20}\]


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