A) same
B) eight times
C) four times
D) twice
Correct Answer: C
Solution :
Increase in temperature of ideal gas from \[27{}^\circ C\]to\[927{}^\circ C\] \[\therefore \] Increase in \[KE=\frac{3}{2}RT\] \[{{T}_{1}}=27+273\Rightarrow 300\text{ }K\] \[{{T}_{2}}=927+27\Rightarrow 1200\text{ }K\] \[\because \] \[KE\propto T\] \[\therefore \] \[\frac{K{{E}_{1}}}{K{{E}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{300}{1200}=\frac{1}{4}\] \[K{{E}_{2}}=4K{{E}_{1}}\] Hence, kinetic energy is increased four times.
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