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Uttarakhand PMT Uttarakhand PMT Solved Paper-2006

  • question_answer
    1 mole. of cone. HCl requires x moles of dil. \[NaOH\]for neutralisation and 1 mole of cone. \[{{H}_{2}}S{{O}_{4}}\]requires y moles of small dil.\[HCl\]. Then which of the following equation is true?

    A)  \[y=\frac{1}{2}x\]         

    B)  \[x=\frac{1}{2}y\]

    C)  \[x=2y\]          

    D)  None of these

    Correct Answer: B

    Solution :

     One mole of\[HCl=1\]equivalent of\[HCl\] = 1 equivalent of \[NaOH=x\] One mole of\[{{H}_{2}}S{{O}_{4}}=2\]equivalent of\[{{H}_{2}}S{{O}_{4}}\] = 2 moles of\[NaOH=y\] \[\therefore \]             \[y=2x\]


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