A) \[11.2\text{ }d{{m}^{3}}\]
B) \[5.6\text{ }d{{m}^{3}}\]
C) \[22.4\text{ }d{{m}^{3}}\]
D) \[1.0\text{ }d{{m}^{3}}\]
Correct Answer: B
Solution :
Mass of\[{{O}_{2}}=\frac{E}{F}\times Q=\frac{8}{F}\times F=8\,g\] Volume of 8g of\[{{O}_{2}}\]at NTP \[=\frac{22.4\times 8}{32}d{{m}^{3}}\] \[=5.6\text{ }d{{m}^{3}}\]
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